How do you differentiate # sin (x/2)#?

1 Answer
Jun 15, 2016

#cos(x/2) * 1/2#

Explanation:

Using the chain rule;
Differentiate the outer function, and then multiply it by the inner function. In this case #sin# is the outer function and #x/2# is the inner function.

The derivative of #sin(x) = cos(x)# and the derivative of #x/2 = 1/2#.

So our final answer when differentiating #sin(x/2)# with respect to x is --> #cos(x/2) * 1/2#