Question

If the pH is 14.75, what is `[OH^-]`?

Answer 1

In aqueous solution under standard conditions, `pH+pOH=14`

Explanation:

Given the above, `pOH` `=` `-0.75`.

Thus `[HO^-]` `=` `10^(-(-0.75))` `=` `10^(+0.75)` `=` `5.62*mol*L^-1`.