Question

What is the limit of `(2x^2-18) / (x+3)` as x approaches -3?

Answer 1

4

Explanation:

when seeing this type of question `0/0`
you need to use L Hospital LAW
`lim_(x->-3)(2x^2-18)/(x+3)`
=`lim_(x->-3)(4x)/x`
=`4`

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May I suggest the following solution ...Tony B

Look at limit ex Maple =-12

Limit ex EfOfEx

If you apply polynomial division you end up with `2x-6`

Or if you factor you have: `(2(x^2-3^2))/(x+3)`

`(2(x-3)cancel((x+3)))/cancel((x+3)) = 2x-6`

So at `x=-3" we have "2(-3)-6 = -12`