How do you solve #(3x)/(x - 2) = 6/(x - 2)#?

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Answer 1 · 2016-06-19T08:18:56

This equation has no solution.

Given:

#(3x)/(x-2) = 6/(x-2)#

Mutiply both sides by #(x-2)# to get:

#3x=6#

Divide both sides by #3# to get:

#x = 2#

Any solution of the original equation must satisfy #x=2#.

However, if we try to substitute #x=2# in the original equation, the denominators on both sides are #0#, so the expressions are undefined.

So #x=2# is a not a solution of the original equation.