Is #f(x)=-x^2+3x-1# increasing or decreasing at #x=1#?
1 Answer
Jun 21, 2016
f(x) is increasing at x = 1
Explanation:
To determine if a function is increasing/decreasing at x = a , evaluate f'(a).
• If f'(a) > 0 , then f(x) is increasing at x = a
• If f'(a) < 0 , then f(x) is decreasing at x = a
#f(x)=-x^2+3x-1rArrf'(x)=-2x+3# and
#f'(1)=-2(1)+3=1# Since f'(1) > 0 , then f(x) is increasing at x = 1
graph{-x^2+3x-1 [-10, 10, -5, 5]}