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Question #b0fbf

1 Answer

Jun 22, 2016

#f'(x)=sinx+xcosx #

Explanation:

#f(x)=x sinx #
#d/dxf(x)g(x)=f'(x)g(x)+f(x)g'(x)#
Use this concept
So
#f'(x)=sinx+xcosx #

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