Question

The heat of vaporization of water is 540 cal/g. How many calories would be needed to convert 3 moles of water to vapor?

Answer 1

`Q=3*molxx18.01*g*mol^-1xx540*cal*g^-1`

`~=` `2500*cal`

Explanation:

Note that here we consider the enthalpy of vaporization ONLY.

Both the water and the steam are considered to be at `100` `""^@C`.