How is the pH of a solution related to the #[H_3O^+]#?

1 Answer
anor277
Jun 23, 2016

#pH=-log_10[H_3O^+]#

Explanation:

So given a neutral solution, #[H_3O^+][HO^-]=10^(-14)#, and since, by definition, #[H_3O^+]=[""^(-)OH]#, i,e,. #[H_3O^+]# #=# #10^-7*mol*L^-1#

And thus #pH# #=# #-log_10(10^-7)# #=# #7# (because #log_(a)a^b# #=# #b# by definition). You might need to review the logarithmic function.

Related questions
See all questions in pH calculations
Impact of this question
2957 views around the world
You can reuse this answer
Creative Commons License