Question

How do you solve `abs( x + 3) <2`?

Answer 1

`x< -1 and x> -5`
In interval notation solution is `(-5, -1)`

Explanation:

`|x+3| < 2 ; x+3 < 2 and x+3 > -2 :. x< -1 and x> -5` In interval notation solution is `(-5, -1)`[Ans]