Question

How do you find the limit of `1/(2x+sinx)` as x approaches `oo`?

Answer 1

0

Explanation:

`sin x in [-1,1] forall x`

so `lim_{x \to oo} y = lim_{x \to oo} 2x + sin x = oo`

`\implies lim_{x \to oo} 1/y = lim_{x \to oo} 1/(2x + sin x) = 0`