How do you solve #4x^(1/4) -3 = 21#?

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Answer 1 · 2016-06-28T19:29:27

You just have to rearrange the equation so you have #x# on one side.

#4x^(1/4)-3=21#

#4x^(1/4)=21+3#

#x^(1/4)=24/4#

#x=(24/4)^4#

and then do the math!

Answer 2 · 2016-06-28T19:32:37

#x = 1296#

Rearrange the equation first:

#4x^(1/4) -3 = 21 rArr 4x^(1/4) = 21+3#

#4x^(1/4) = 24 " divide by 4"#

#x^(1/4) = 6#

#(x^(1/4))^4 = 6^4 " raise both sides to 4th power"#

#x = 1296#