How do you find four consecutive integers such that 2 times the sum of the first and fourth is 24 less than 6 times the third?
1 Answer
Jun 29, 2016
9,10,11,12
Explanation:
let x the first numbers,
so x+1 is the second,
x+2 the third,
x+3 the fourth
the sum of the first and fourth is
2 times this sum is
6 times the third is 6(x+2)
so the requested equation to solve will be:
Let's solve it:
