We have an equation with a variable on both sides as well as a square root operation.
#sqrt(3x + 28) = x# To undo the square root, we need to square both sides. That way, we get rid of the square root operation and wont have to worry about.
#(sqrt(3x + 28))^2 = (x)^2# Squared both sides.
#3x + 28 = x^2# The square root canceled out when we squared it on the left side.
#x^2 - 3x - 28 = 0# Got all terms to one side and set equation equal to zero, so we can factor next.
#(x - 7)(x + 4) = 0# Factored the equation from before.
#x = 7, x = -4# Since the equation above was set equal to zero, we can take the values inside each of the parentheses and set them equal to zero. The solutions for #x# that we get from there are your answers.
Remember to check your work, in case any of the solutions don't work or a mistake was made. I checked the work here and all solutions work.
