How do you solve #25/y=5/15#?
1 Answer
Jul 2, 2016
y = 75
Explanation:
When we have a fraction equal to another fraction. To solve we
#color(blue)"cross-multiply"#
#rArr(5xxy)=(25xx15)rArr5y=25xx15# divide both sides by 5
#(cancel(5)^1y)/cancel(5)^1=(25xxcancel(15)^3)/cancel(5)^1#
#rArry=25xx3=75#
