Question

What is the `pOH` of a `6.5*10^-12` `M` `OH^-` solution?

Answer 1

`pOH~=11.`

Explanation:

`pOH=-log_10[HO^-]`

`-log_10{6.5xx10^-12}` `=` `11.2`

What is the `pH` of this solution? You should not need a calculator.