Question

What is the force, in terms of Coulomb's constant, between two electrical charges of `-45 C` and `42 C` that are `15 m` apart?

Answer 1

`F= -8.4K`

Explanation:

Force experienced between two charged bodies is `F=K(q_1q_2)/r^2`

Taking `q_1=-45C`, `q_2=42C` and `r=15m`
We get
`F=K(-cancel45^1*42)/(cancel15^1*cancel15^5)`

So, the remainder is left to as an exercise to the reader.