Question #5c707
1 Answer
Here's how you can do that.
Explanation:
Ammonium phosphate,
As you can see from the compound's chemical formula, one formula unit of ammonium phosphate contains
- three ammonium cations,
#color(blue)(3) xx "NH"_4^(+)# - one phosphate anion,
#1 xx "PO"_4^(3-)#
This of course means that one mole of ammonium phosphate will contain
Now, each ammonium cation is made up of
- one atom of nitrogen,
#1 xx "N"# - four atoms of hydrogen,
#color(red)(4) xx "H"#
Since one mole of ammonium cations will contain
#color(blue)(3) color(darkred)(cancel(color(black)("moles NH"_4^(+)))) * (color(red)(4)color(white)(a)"moles of H")/(1color(darkred)(cancel(color(black)("mole NH"_4^(+))))) = color(green)(|bar(ul(color(white)(a/a)color(black)("12 moles of H")color(white)(a/a)|)))#
Therefore, you can say that every mole of ammonium phosphate contains a total of
You can expand this to say that for any number of moles of ammonium chloride given to you,
#n color(red)(cancel(color(black)("moles"color(white)(a)("NH"_4)_3"PO"_4))) * "12 moles H"/(1color(red)(cancel(color(black)("mole"color(white)(a)("NH"_4)_3"PO"_4)))) = (12 * n)color(white)(a)"moles H"#