Question

How do you find the definite integral of `sqrt(y+1)*dy` from `[-1, 0]`?

Answer 1

`= 2/3`

Explanation:

`int_{-1)^0 dy qquad sqrt(y+1)`

this is simply the power rule ie `int du qquad u^n = n^{n+1}/(n+1)`

So

`=[2/3 (y+1)^(3/2)]_{-1)^0`

`=[2/3 (0+1)^(3/2)] - [2/3 (-1+1)^(3/2)] = 2/3`