Question

Arsenic reacts with chlorine to form a chloride. If 1.587 g of arsenic reacts with 3.755 g of chlorine what is the empirical formula of the chloride?

Answer 1

`AsCl_5`

Explanation:

`"Moles of arsenic"` `=` `(1.587*g)/(74.92*g*mol^-1)=0.0212*mol`.

`"Moles of chlorine"` `=` `(3.755*g)/(35.45*g*mol^-1)=0.106*mol`.

We divide thru by the lowest molar quantity to give `AsCl_5`. This is not chemical you would find in a bottle on a shelf.