Question

What is the perimeter of a triangle with corners at `(7 ,5 )`, `(1 ,6 )`, and `(4 ,8 )`?

Answer 1

Perimeter of the triangle is `13.93(2dp)` unit

Explanation:

Side `A= sqrt((7-1)^2+(5-6)^2)= sqrt(36+1)=sqrt 37 = 6.08`
Side `B= sqrt((1-4)^2+(6-8)^2)= sqrt(9+4)=sqrt 13 = 3.61`
Side `C= sqrt((4-7)^2+(8-5)^2)= sqrt(9+9)=sqrt 18 = 4.24`
Perimeter of the triangle is `P=(6.08+3.61+4.24)= 13.93(2dp)`unit [Ans]