How do you differentiate Sin ^ 3 xsin3x?

1 Answer
Jul 13, 2016

dy/dx = 3sin^2(x) *cos xdydx=3sin2(x)cosx

Explanation:

In order to differentiate sin^3(x)sin3(x), we need to use a chain rule, which tells us that

d/dx[f(g(x))] = f'(g(x))*g'(x)

Letting y = sin^(3)(x), then

dy/dx = 3sin^2(x) *cos x

In this problem, we've also performed the power rule, namely by subtracting 1 from the power of 3 on the sin x term, which is why we end up with a sin^2(x).