Three consecutive integers add up to 24. What are they?

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Three consecutive integers add up to 24. What are they?

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Answer 1 · 2016-07-14T19:30:55

$7$ $7$ , $8$ $8$ , and $9$ $9$

Explanation:

Integer 1: $n$ $n$
Integer 2: $n + 1$ $n+1$
Integer 3: $n + 2$ $n+2$

I added $1$ $1$ or $2$ $2$ to $n$ $n$ because we don't know what number is after $n$ $n$ , but we do know that they are consecutive.

Let's add these three integers and let them equal $24$ $24$ .

$n + (n + 1) + (n + 2) = 24$ $n + (n+1) + (n+2) = 24$

Solve for $n$ $n$ .

$3 n + 3 = 24$ $3n + 3 = 24$

$3 n = 21$ $3n = 21$

$n = 7$ $n = 7$

We found that $n$ $n$ is equal to $7$ $7$ . We can simply add $1$ $1$ to find the next integer and add $2$ $2$ to find the third integer. The three integers are $7$ $7$ , $8$ $8$ , and $9$ $9$ .

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Three consecutive integers add up to 24. What are they?

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