Question

What is the perimeter of a triangle with corners at `(2 ,6 )`, `(9 ,2 )`, and `(3 ,1 )`?

Answer 1

The perimeter of the triangle is `19.24(2dp)` unit

Explanation:

We know distance formula; `d=sqrt((x_1-x_2)^2+(y_1-y_2)^2) :.`
Side`A=sqrt((2-9)^2+(6-2)^2))=sqrt(49+16)=sqrt65=8.06`
Side`B=sqrt((9-3)^2+(2-1)^2))=sqrt(36+1)=sqrt37=6.08`
Side`C=sqrt((3-2)^2+(1-6)^2))=sqrt(1+25)=sqrt26=5.1 :.`
Perimeter `P=(8.06+6.08+5.1)=19.24(2dp)`unit[Ans]