Question

How do you condense `6log_3 u + 6log_3 v`?

Answer 1

`log_3 (uv)^6`

Explanation:

If logs are being added, then the numbers are multiplied.

`6log_3 u + 6log_3 v`

=`log_3 u^6 + log_3 v^6`

=`log_3 (u^6 xx v^6)`

=`log_3 (uv)^6`