Question

How do you solve `10^(-12x)+6=100`?

Answer 1

`x = -0.1644`

Explanation:

`10^(-12x)+6=100`

`10^(-12x)=94`

As the variable is in the index, we will use logs.

`log10^(-12x)=log94`

`-12x xxlog10=log94 " "log 10 = 1`

`x =log94/(-12)`

`x = -0.1644`