How do you condense #ln3+1/3ln(4 - x^2) - ln x #?

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Answer 1 · 2016-07-16T21:27:02

=# ln[(3(4 - x^2)^(1/3))/x]# or it can be written as

# ln[(3xxroot(3)(4 - x^2))/x]#

If logs are added, the numbers are multiplied.
If logs are subtracted, the numbers are divided.

#ln3+1/3ln(4 - x^2) - ln x #

=#ln3+ln(4 - x^2)^(1/3) - ln x " power law"#

=# ln[(3(4 - x^2)^(1/3))/x]#

or it can be written as

# ln[(3xxroot(3)(4 - x^2))/x]#