How do you simplify #9y^4j^2y^-9#?

1 Answer
Acquaintance
Jul 17, 2016

#color(green)((9j^2)/y^5)#

Explanation:

Note this law: #a^-b = 1/a^b#

and this as well: #a^b/a^c = a^(b-c)#
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#9y^4j^2y^-9#

Follow the first rule mentioned above and rewrite the expression:

#(9y^4j^2)/y^-9#

Now use the second law to simplify the #y# terms in the numerator and denominator:

#9y^(4-9)j^2#

#9y^-5j^2#

Jump back to the first law and rewrite the negative exponent:

#color(green)((9j^2)/y^5)#

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