Question

How do you integrate `[1/(x^2-4)] dx`?

Answer 1

`int (1/(x^2-4)) dx=1/4*ln ((x-2)/(x+2))+C`

Explanation:

Use the formula

`int dx/(u^2-a^2)=1/(2a)*ln ((u-a)/(u+a))+C`

God bless....I hope the explanation is useful.