How do you solve lnx-ln(1/x)=2?

1 Answer
Jul 19, 2016

x = ± e

Explanation:

We can apply a property of logarithms, namely the property

ln(a) - ln(b) = ln(a/b)

Thus, we have

ln(x) - ln(1/x) = 2

ln(x/(1/x)) = 2

ln(x^2) = 2

x^2 = e^2

x = ± e