A charge of $40 C$ $40 C$ passes through a circuit every $8 s$ $8 s$ . If the circuit can generate $12 W$ $12 W$ of power, what is the circuit's resistance?

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A charge of $40 C$ $40 C$ passes through a circuit every $8 s$ $8 s$ . If the circuit can generate $12 W$ $12 W$ of power, what is the circuit's resistance?

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Answer 1 · 2016-07-19T23:15:10

I found: $0.48Omega$

Explanation:

You can use your data to evaluate current as the rate of flow of charge in time to get:
$I=Q/t=40/8=5A$
We the use the definition of electrical power $P=V*I$ and Ohm's Law, $V=R*I$ , to get:
$P=I^2*R$
And
$12=5^2*R$
$R=12/25=0.48Omega$

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A charge of $40 C$ $40 C$ passes through a circuit every $8 s$ $8 s$ . If the circuit can generate $12 W$ $12 W$ of power, what is the circuit's resistance?

1 Answer

Explanation:

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A charge of 40 C40C40 C passes through a circuit every 8 s8s8 s. If the circuit can generate 12 W12W12 W of power, what is the circuit's resistance?

1 Answer

Explanation:

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A charge of $40 C$ $40 C$ passes through a circuit every $8 s$ $8 s$ . If the circuit can generate $12 W$ $12 W$ of power, what is the circuit's resistance?