How do you solve #-5/4a + 1 + 5/2a = 21/16#?

1 Answer
Jul 22, 2016

#a = 9/5#

Explanation:

#-5/4a + 1 + 5/2a = 21/16" get rid of the denominators"#

#(-5acolor(blue)(xx16))/4 + 1color(blue)(xx16) + (5acolor(blue)(xx16))/2 = (21color(blue)(xx16))/16" "LCM = color(blue)(16)#

#(-5acolor(blue)(xxcancel16^4))/cancel4 + 1color(blue)(xx16) + (5acolor(blue)(xxcancel16^8))/cancel2 = (21color(blue)(xxcancel16))/cancel16#

#-20a + 16 +40a = 21#

#20a = 36#

#a = 36/20 = 9/5#