How do you solve #(x-5)^2=9#?

1 Answer
georgef
Jul 25, 2016

Only two numbers are such that raised to the square #=9#

Explanation:

If a number to the square #=9#, it is either #3# or #-3#. So, either:

#x-5=3#, or #x-5=-3#. Then, it is either #x=3+5# or #x=-3+5#

The two solutions are then #x=8# and #x=2#

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