Question

What is the standard form equation for the parabola y=(x-4)(x-8)?

Answer 1

`y+4=(x-6)^2`.

Explanation:

Given that, `y=(x-4)(x-8)=x^2-12x+32`

`rArr y-32=x^2-12x`

Completing the square on R.H.S.,

`y-32+36=x^2-12x+36=(x-6)^2`

`:. y+4=(x-6)^2`.