Question

How do you find the perimeter of a rectangular object which has a length of square root of 128 feet and a width of square root of 200 feet?

Answer 1

The Perimeter =`36sqrt2feet`.

Explanation:

Length `l=sqrt128=sqrt(64*2)=8sqrt2`, and,

Width `w=sqrt200=sqrt(100*2)=10sqrt2`.

Hence,

The Perimeter `=2(l+w)=2(8sqrt2+10sqrt2)=2*18sqrt2=36sqrt2feet`