How do you find the limit of #(1/(1+h)) - 1 / h# as h approaches 0?

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Answer 1 · 2016-07-31T08:03:40

#lim_(h to 0^-) (1/(1+h)) - 1 / h = oo#

#lim_(h to 0^+) (1/(1+h)) - 1 / h = - oo#

#lim_(h to 0) (1/(1+h)) - 1 / h#

#lim_(h to 0) = (h - (1+h))/(h(1+h))#

#lim_(h to 0) = (- 1)/(h(1+h))#

#= - 1/h #

#lim_(h to 0^-) (1/(1+h)) - 1 / h = oo#

#lim_(h to 0^+) (1/(1+h)) - 1 / h = - oo#