Two parallel plates are charged up such that the electric field between them is 7.93 x 10^-1N/C. A particle with a charge of 1.67 x 10^-4C is placed between the plates. How much force is acting on this particle?

1 Answer
Maxwell
Aug 2, 2016

#F# = # 1.32 * 10^-2N#

Explanation:

A parallel plate capacitor sets up an electric field which is nearly constant. Any charge present in the field will feel a force. The equation to use is:

#F_E = E*q#

#F_E = "Force" (N)#
#E = "Electric field" (N/C)#
#q = "charge" (C)#

#F_E# = #(7.93 * 10^1)""N/C"# * #(1.67 * 10^-4)C"#

#F_E# = # 1.32 * 10^-2 N#

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