How do you find $- i + (7 - 5 i) - 3 (2 - 3 i)$ $-i+(7-5i)-3(2-3i)$ ?

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Answer 1 · 2016-08-03T01:56:55

$1 + 3 i$ $1+3i$

$- i + (7 - 5 i) - 3 (2 - 3 i)$ $-i + (7-5i)-3(2-3i)$

Expand:
$\to - i + 7 - 5 i - 6 + 9 i$ $-> -i + 7-5i-6+9i$

Sum real and imaginary parts:
$\to 7 - 6 + 9 i - 5 i - i$ $-> 7-6 +9i-5i-i$

$= 1 + 3 i$ $=1+3i$

How do you find −i+(7−5i)−3(2−3i)-i+(7-5i)-3(2-3i)?