Question

`F( x ; b) = log_b(x+1/log_b(x+1/log_b(x+...))), x>=b>1.`How do you approximate F(15, 10)=1.19958, nearly?

Answer 1

Contribution

Explanation:

From

`y = log_b(x+1/y)` and calling `b = z` the surface

`G(x,y,z) = z^y-x-1/y = 0` for

#( (-5 < x < 5), (-5 < y < 5), (0< z < 5))#

locally, has the aspect below