How do you solve #-2(x-5)-12<=4+6(x+3)#?

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Answer 1 · 2016-08-03T22:50:57

#x >=-3#

Treat a linear inequality in the same way that you solve an equation.

Except: if you multiply or divide by a negative number, the inequality sign changes around.

#-2(x-5)-12<=4+6(x+3)#

#-2x +10 -12 <= 4+6x+18#

#-2x -2 <= 6x+22#

#-2-22 <= 6x+2x" x terms on right makes them positive"#

#-24<= 8x " divide by 8 on each side"#

#(-24)/8 = (8x)/8#

#-3 <= x" "rArr x >=-3#