Question

How do you find `f(g(x))` given `f(x)=-3x+7` and `g(x)=x^2-8`?

Answer 1

`f(g(x))=-3x^2+31`

Explanation:

`f(x)=-3x+7 and g(x)=x^2-8`
`f(g(x))` => AKA: `fog(x)` => or: f of `g(x)`:
therefore:
`f(g(x))=f(x^2-8)`
`=-3(x^2-8)+7`
`=-3x^2+24+7`
`=-3x^2+31`