How do you solve -8.7e^(6.6-6x)-7=-32.8? Precalculus Properties of Logarithmic Functions Natural Logs 1 Answer Ratnaker Mehta Aug 4, 2016 x=0.9188 Explanation: Let us rewrite the given eqn., by removing all -ve signs, as 8.7e^(6.6-6x)+7=32.8 rArr 8.7e^(6.6-6x)=25.8 rArr e^(6.6-6x)=25.8/8.7 rArr log_10{e^(6.6-6x)}=log_10 25.8-log_10 8.7 rArr (6.6-6x)log_10e=1.4116-0.9395=0.4721 rArr (6.6-6x)(0.4343)=0.4721 rArr (6.6-6x)=0.4721/0.4343=1.087 rArr (6.6-1.087)/6=x=0.9188. Answer link Related questions What is the natural log of e? What is the natural log of 2? How do I do natural logs on a TI-83? How do I find the natural log of a fraction? What is the natural log of 1? What is the natural log of infinity? Can I find the natural log of a negative number? How do I find a natural log without a calculator? How do I find the natural log of a given number by using a calculator? How do I do natural logs on a TI-84? See all questions in Natural Logs Impact of this question 1464 views around the world You can reuse this answer Creative Commons License