Question

How do you evaluate `(a^2 - 2(b^2-a)) /(2 +a)` for a = 3 and b= 5?

Answer 1

`=-7`

Explanation:

`(a^2-2(b^2-a))/(2+a)` for `a=3` and `b=5`
`=(3^2-2(5^2-3))/(2+3)`
`=(9-2(25-3))/5`
`=(9-2(22))/5`
`=(9-44)/5`
`=-35/5`
`=-7`