What is the perimeter of a triangle with corners at #(1 ,4 )#, #(5 , 2 )#, and #(9 ,7 )#?

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What is the perimeter of a triangle with corners at #(1 ,4 )#, #(5 , 2 )#, and #(9 ,7 )#?

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Answer 1 · 2016-08-07T18:23:39

#=19.4#

Explanation:

So sides of the triangle with corners at #(1,4),(5,2), and (9,7)# are as follows
Side #1#
#sqrt((5-1)^2+(4-2)^2)#
#=sqrt(4^2+2^2#
#=sqrt(16+4)#
#=sqrt20#
#=4.5#
Side #2#
#=sqrt((9-5)^2+(7-2)^2#
#=sqrt(4^2+5^2#
#=sqrt(16+25)#
#=sqrt41#
#=6.4#
Side #3#
#sqrt((9-1)^2+(7-4)^2)#
#=sqrt(8^2+3^2#
#=sqrt(64+9)#
#=sqrt73#
#=8.5#
So perimeter #=4.5+6.4+8.5=19.4#

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What is the perimeter of a triangle with corners at #(1 ,4 )#, #(5 , 2 )#, and #(9 ,7 )#?

1 Answer

Explanation:

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