Question

How do you write `log_243 3 =1/5` in exponential form?

Answer 1

I found: `3=243^(1/5)`

Explanation:

You can use the definition of log where the base of the log `243` becomes the base of the exponential with `1/5` as exponent; you get:
`log_(243)3=1/5`
`3=243^(1/5)`

or: `3=243^(1/5)=root5(243)`