How do you solve #ln3+ln(2x^2+4)=ln12#? Precalculus Properties of Logarithmic Functions Natural Logs 1 Answer Gerardina C. Aug 10, 2016 x=0 Explanation: Since #lna+lnb=ln(ab)#, then #ln3+ln(2x^2+4)=ln12# is equivalent to: #ln(3(2x^2+4))=ln12#. that's equivalent to: #3(2x^2+4)=12# #6x^2+12=12# #6x^2=0# #x=0# Answer link Related questions What is the natural log of e? What is the natural log of 2? How do I do natural logs on a TI-83? How do I find the natural log of a fraction? What is the natural log of 1? What is the natural log of infinity? Can I find the natural log of a negative number? How do I find a natural log without a calculator? How do I find the natural log of a given number by using a calculator? How do I do natural logs on a TI-84? See all questions in Natural Logs Impact of this question 2307 views around the world You can reuse this answer Creative Commons License