Question

What is `f(-2)` if `f(x)=-2x^2-4x`?

Answer 1

`f(-2)=0`.

Explanation:

To find `f(-2)`, given, `f(x)=-2x^2-4x......(star)`, we have to

substitute, in the formula `(star)` of `f(x), x=-2`.

Therefore, `f(-2)=-2(-2)^2-4(-2)=-2*4+8=-8+8=0`.