Question

How do you find the magnitude <2,-3>?

Answer 1

`||A||=sqrt 13" "unit`

Explanation:

`"the magnitude of "A=<x,y> " will be " ||A||=sqrt(x^2+y^2)," if A= < x, y>"`

`A= <2,-3>`

`x=2" ; "y=-3`

`||A||=sqrt(2^2+(-3)^2)`

`||A||=sqrt(4+9)`

`||A||=sqrt 13" "unit`