Question

How do you evaluate the limit `(x^2+4x+3)/(x+3)` as x approaches `-3`?

Answer 1

`= -2`

Explanation:

`lim_{x to -3} (x^2+4x+3)/(x+3)`

`= lim_{x to -3} ((x+3)(x+1))/(x+3)`

let `y = x + 3`

`= lim_{y to 0} y/y (y - 2)`

`= -2`