If $a = \frac{4}{5}$ $a=4/5$ and $b = \frac{3}{5}$ $b=3/5$ , what is $23 - (a + b)$ $23-(a+b)$ ?

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Answer 1 · 2016-08-12T00:05:16

$21 \frac{3}{5}$ $21 3/5$

$a + b = \frac{4}{5} + \frac{3}{5} = \frac{7}{5} = 1 \frac{2}{5}$ $a + b = 4/5 + 3/5 = 7/5 =1 2/5$

Substitute the given values for $a and b$ $a and b$

$23 - (\frac{4}{5} + \frac{3}{5}) = 23 - 1 \frac{2}{5}$ $23 - (4/5+3/5) = 23 -1 2/5$

$23 - 1 - \frac{2}{5} = 22 - \frac{2}{5}$ $23-1 -2/5 = 22-2/5$

$21 \frac{3}{5}$ $21 3/5$

If a=45a=4/5 and b=35b=3/5, what is 23−(a+b)23-(a+b)?