Question

If `3n-7=5(2n+7)`, what is `n^2/(2n-6)`?

Answer 1

`n=-6 -> n^2/(2n-6) = -2`

Explanation:

`3n -7 = 5(2n+7)`

`3n-7=10n+35`

`-7n=42 -> n=-6`

`n^2/(2n-6)` with `n=-6 = (-6)^2/(2*(-6)-6)`

`=36/-18 = -2`